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Free Fall Calculator

Fall time, impact velocity and distance under gravity

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Free fall: gravity, and nothing else

Free fall is the idealised case where the only force acting on an object is gravity — no air resistance, no wind, no terminal velocity. It is the version taught first in physics because it is the version with a clean closed-form answer, and it is a genuinely good approximation for dense, compact objects falling modest distances: a dropped tool, a stone off a bridge, the height of a fall in a physics problem. It stops being a good approximation for anything light and wide falling a long way, which is covered below.

The three equations

t = √(2h / g)v = g × th = ½ × g × t²

Enter a height and get the fall time and impact velocity, or enter a time and get the height fallen and velocity reached — the same three equations rearranged for whichever variable you have. Standard gravity g = 9.80665 m/s² is used throughout, the internationally defined value for Earth's surface.

Worked examples

HeightFall timeImpact velocity
1 m0.45 s4.4 m/s (16 km/h)
10 m (a three-storey building)1.43 s14.0 m/s (50 km/h)
100 m4.52 s44.3 m/s (159 km/h)
1,000 m14.3 s140 m/s (505 km/h) — before accounting for air resistance

Doubling the height does not double the fall time — time scales with the square root of height, which is why the fall time barely increases from 100 m to 1,000 m in relative terms while the impact speed grows much faster.

Where the idealised answer stops being realistic

Air resistance grows with the square of speed, so it matters very little for a short drop and increasingly for a long one. A coin dropped from a table experiences negligible air resistance and the formulas above are essentially exact. A skydiver falling for thousands of metres reaches terminal velocity — the speed at which air resistance exactly balances gravity, typically around 195 km/h (54 m/s) for a body in a stable belly-down position — well before hitting the ground, and the formulas above would badly overstate the actual impact speed for that case. As a rough guide, the free-fall equations are reliable up to perhaps a few hundred metres for a dense, compact object, and increasingly wrong beyond that or for anything with significant surface area relative to its weight.

Common physics-class checks

  • Mass does not appear anywhere in the equations. In true free fall, a hammer and a feather fall at the same rate — famously demonstrated on the airless Moon during Apollo 15. On Earth, the feather's much larger surface area relative to its weight means air resistance dominates almost immediately, which is a statement about air resistance, not about gravity treating them differently.
  • Initial velocity is assumed to be zero — an object simply released, not thrown. A thrown or launched object needs the fuller projectile motion equations, which this calculator does not cover.

Frequently asked questions

Why don't heavier objects fall faster?

In true free fall, gravitational acceleration is the same for every mass — a fact famously demonstrated with a hammer and feather on the airless Moon. On Earth, heavier or more compact objects merely feel less relative air resistance, which is a different effect entirely.

Does this work for objects thrown downward or upward, not just dropped?

No — it assumes zero initial velocity. An object with initial speed needs the fuller projectile motion equations, which add that initial velocity into the calculation.

Why does my answer not match a real drop I timed?

Air resistance, reaction time in manual timing, and the practical difficulty of measuring height and time precisely all introduce error that the idealised formula doesn't include.

What value of gravity does this use?

9.80665 m/s², the standard internationally defined value at Earth's surface. Actual local gravity varies very slightly with latitude and altitude — negligibly for any everyday calculation.

Is this valid on other planets?

The equations are the same everywhere; only g changes — about 1.62 m/s² on the Moon, 3.72 m/s² on Mars. This calculator uses Earth's value.

Is my data uploaded anywhere?

No. The calculation runs in your browser.

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